The mean of the following data is 8.

x 3 5 7 9 11 13

y 6 8 15 p 8 4

The value of p is
(a) 23
(b) 24
(c) 25
(d) 21

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Solution

(c) 25

x _y _{x $\times$ y}

3 6 18

5 8 40

7 15 105

9 p 9p

11 8 88

13 4 52

Total 41 + p 303 + 9p

$Now, Mean = \frac{303 + 9 p}{41 + p} Given : Mean = 8 ∴ \frac{303 + 9 p}{41 + p} = 8 \Rightarrow 303 + 9 p = 328 + 8 p \Rightarrow p = 25$

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Similar questions

The mean of the following data is 8.
$\begin{matrix} x & 3 & 5 & 7 & 9 & 11 & 13 y & 6 & 8 & 15 & p & 8 & 4 \end{matrix}$
then, the value of p is
(a) 23
(b) 24
(c) 25
(d) 21

Q. The mean of the following frequency distribution is 8. Find the value of p.

x	3	5	7	9	11	13
f	6	8	15	p	8	4

Q. Making use of the data given below, calculate the coefficient of correlation.

X	10	6	9	10	12	13	11	9
Y	9	4	6	9	11	13	8	4

Q. Given the following pair of values of the variables X and Y:

X	8	10	12	11	9	7	13	14	15
Y	5	7	9	8	6	4	10	11	12

Also describe relationship between X and Y.

Q. In which of the following tables x and y vary inversely:
(i)

x	4	3	12	1
y	6	8	2	24

(ii)

x	5	20	10	4
y	20	5	10	25

(iii)

x	4	3	6	1
y	9	12	8	36

(iv)

x	9	24	15	3
y	8	3	4	25

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x	_y	_{x $\times$ y}
3	6	18
5	8	40
7	15	105
9	p	9p
11	8	88
13	4	52
Total	41 + p	303 + 9p

The mean of the following data is 8. x 3 5 7 9 11 13 y 6 8 15 p 8 4 The value of p is (a) 23 (b) 24 (c) 25 (d) 21

(c) 25 x y x×y 3 6 18 5 8 40 7 15 105 9 p 9p 11 8 88 13 4 52 Total 41 + p 303 + 9p Now,Mean=303+9p41+pGiven:Mean=8∴303+9p41+p=8⇒303+9p=328+8p⇒p=25

The mean of the following data is 8.

x 3 5 7 9 11 13

y 6 8 15 p 8 4

The value of p is
(a) 23
(b) 24
(c) 25
(d) 21

(c) 25

x _y _{x $\times$ y}

3 6 18

5 8 40

7 15 105

9 p 9p

11 8 88

13 4 52

Total 41 + p 303 + 9p

$Now, Mean = \frac{303 + 9 p}{41 + p} Given : Mean = 8 ∴ \frac{303 + 9 p}{41 + p} = 8 \Rightarrow 303 + 9 p = 328 + 8 p \Rightarrow p = 25$