The mean of the following distribution is - - x i 10 13 16 19- f i 2 5 7 6- -

The correct option is A 15.55 Mean of ungrouped frequency distribution is given by x̅ = ∑_i=1^n f_ix_i/∑_i=1^n f_i =(10× 2+13 × 5+16×7+19×6)/(2+5+7+6) =311/20 ...

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Standard IX

Mathematics

Frequency Table & Its Average

The mean of t...

Question

The mean of the following distribution is ____.

$\begin{matrix} x_{i} & 10 & 13 & 16 & 19 f_{i} & 2 & 5 & 7 & 6 \end{matrix}$

15.55

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15.35

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14.3

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Solution

The correct option is A
15.55

Mean of ungrouped frequency distribution is given by

$¯ x = \frac{\sum_{i = 1}^{n} f_{i} x_{i}}{\sum_{i = 1}^{n} f_{i}}$
$= \frac{(10 \times 2 + 13 \times 5 + 16 \times 7 + 19 \times 6)}{(2 + 5 + 7 + 6)}$
$= \frac{311}{20}$

Therefore, the mean of the data is 15.55.

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The mean of the following distribution is ____. xi10131619fi2576

The correct option is A 15.55 Mean of ungrouped frequency distribution is given by ¯x=∑ni=1fixi∑ni=1fi =(10×2+13×5+16×7+19×6)(2+5+7+6) =31120 Therefore, the mean of the data is 15.55.

The mean of the following distribution is ____.

$\begin{matrix} x_{i} & 10 & 13 & 16 & 19 f_{i} & 2 & 5 & 7 & 6 \end{matrix}$

The correct option is A
15.55

Mean of ungrouped frequency distribution is given by

$¯ x = \frac{\sum_{i = 1}^{n} f_{i} x_{i}}{\sum_{i = 1}^{n} f_{i}}$
$= \frac{(10 \times 2 + 13 \times 5 + 16 \times 7 + 19 \times 6)}{(2 + 5 + 7 + 6)}$
$= \frac{311}{20}$

Therefore, the mean of the data is 15.55.