Finding Mean for Grouped Data When Class Intervals Are Not Given
The mean of t...
Question
The mean of the following frequency distribution is 16.6
xi
8
12
15
18
20
25
30
Total
fi
12
16
p
24
16
q
4
100
A
p=20
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B
q=8
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C
p=8
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D
q=20
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Solution
The correct options are Aq=8 Bp=20 We prepare the table as above. Here, ∑fi=72+p+q. But, ∑fi=100 (given). ∴72+p+q=100 p+q=28 Also, mean = ∑fixi∑fi =1160+15p+25q72+p+q =1160+15(p+q)+10q72+(p+q) =1160+15×28+10q72+28=1580+10q100 But mean = 16.6 (given) ∴1580+10q100=16.6 1580+10q=1660 10q=80 q=8 p+q=28 p=28−q=28−8=20 Hence, p=20 and q=8