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Question

The mean of the following frequency distribution is 16.6

xi 8 12 15 18 20 25 30 Total
fi 12 16 p 24 16 q 4 100

A
p=20
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B
q=8
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C
p=8
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D
q=20
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Solution

The correct options are
A q=8
B p=20
We prepare the table as above.
Here, fi=72+p+q.
But, fi=100 (given).
72+p+q=100
p+q=28
Also, mean = fixifi
=1160+15p+25q72+p+q
=1160+15(p+q)+10q72+(p+q)
=1160+15×28+10q72+28=1580+10q100
But mean = 16.6 (given)
1580+10q100=16.6
1580+10q=1660
10q=80
q=8
p+q=28
p=28q=288=20
Hence, p=20 and q=8
839951_242707_ans_991e87873c454a899e1c635f1b94cfca.bmp

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