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Question

The mean of the following frequency distribution is 2117. Find the value of f
C.I0-1010-2020-3030-4040-50
f82231f2

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Solution

¯¯¯x=2112=1487 [ Given ]

C.Ifi xi fixi
010 8 5 40
1020 22 15 330
2030 31 25 775
3040 f 35 35f
4050 2 45 90
fi=63+f fixi=1235+35f
¯¯¯x=fixifi
1487=1235+35f63+f
148(63+f)=7(1235+35f)
9324+148f=8645+245f
97f=679
f=7


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