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Question

The mean of the series x1,x2,x3,.......,xn is ¯x. If x2 is replaced by λ, then the new mean is


A

¯xx2+λ

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B

¯xx2λn

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C

(n1)¯x+λn

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D

n¯xx2+λn

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Solution

The correct option is D

n¯xx2+λn


¯x=x1+x2+x3+....+xnnn¯x=x1+x2+....+xnx1+x3+....+xn=n¯xx2New mean=x1+λ+x3+....+xnnn¯xx2+λn


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