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Question

The mean of the values 0,1,2,,n having corresponding weight nC0,nC1,nC2,nCn, respectively is

A
2nn+1
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B
2n+1n(n+1)
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C
n+12
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D
n2
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Solution

The correct option is D n2
¯¯¯x=0.1+1.nC1+2.nC2.+3.nC3+n.nCn1+nC1+nC2+..........+nCn
=nr=0r.nCrnr=0=nr=1r.nrn1Cr1nr=0nCr==nnr=1n1Cr1nr=0nCr
=n.2n12n=n2

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