Mean of three numbers = 40 and lowest number= 19 [given]
Let the three observations be 19, x and y, respectively.
∴ Mean=Sum of all observationsTotal number of observations⇒ 40=19+x+y3 [∵ mean=40, given]⇒ 3×40=19+x+y
⇒ 120 = 19 + x + y
⇒ x + y = 120 - 19
⇒ x + y = 101
Since, 19 is the lowest observation.
Hence, for the highest possible value of remaining two numbers, one must be 20.
Let x = 20
From Eq. (i), we get
20 + y = 101
⇒ y = 101 - 20
⇒ y = 81