The mean proportional between 6and24 is
8
12
18
24
Let the mean proportional be x, then
6:x::x:24
Now, if a:b::c:dare in proportion.
then, a×d=b×c ---------------------------------eq(1)
So, here we have 6:x::x:24
a=6,b=x,c=x,d=24
by using eq(1) we have
⇒6×24=x×x⇒x2=144⇒x=144⇒x=12
Hence, the mean proportional between 6and24 is 12.
Therefore, OPTION (ii) is correct.
Find the mean proportional between:(i) 6 and 24(ii) 3 and 27(iii) 0.4 and 0.9
Find the mean proportional between :
(i) 6+3√3 and 8−4√3
(ii) a - b and a3−a2b.
If y is the mean proportional between x and z ; show that xy + yz is the mean proportional between x2+y2 and y2+z2.