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Byju's Answer
Standard XII
Mathematics
Onto Function
The mean valu...
Question
The mean value of integral ( sin theta d theta) where the limit is pie to 0 is
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Q.
The value of integral
θ
∫
0
ln
(
1
+
tan
θ
tan
x
)
d
x
,
θ
∈
(
0
,
π
2
)
is equal to
Q.
If the real part of the complex number
(
1
−
cos
θ
+
2
i
sin
θ
)
−
1
is
1
5
for
θ
∈
(
0
,
π
)
,
then the value of the integral
θ
∫
0
sin
x
d
x
is equal to :
Q.
The value of the integral
∫
sin
θ
.
sin
2
θ
(
sin
6
θ
+
sin
4
θ
+
sin
2
θ
)
√
2
sin
4
θ
+
3
sin
2
θ
+
6
1
−
cos
2
θ
d
θ
is
(
where
c
is a constant of integration
)
Q.
The value of
∫
sin
θ
d
θ
(
4
+
cos
2
θ
)
(
2
−
sin
2
θ
)
is equal to (where
C
is integration constant)
Q.
Consider the geometric progression
S
=
1
+
2
sin
2
θ
+
4
sin
4
θ
+
8
sin
6
θ
+
.
.
.
.
.
up to infinite terms, where S is a finite number and
θ
≠
n
π
2
where n
ε
I.
Then Minimum integral value of S is equal to
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