The mean weight per teacher in a group of $7$ teachers is $55$ kg. The individual weights of $6$ of them are $52$ kg, $58$ kg, $55$ kg, $53$ kg, $56$ kg and $54$ kg, the weight of the other teacher is $x$ kg, then the value of $x$ is

55

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57

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58

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52

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Solution

The correct option is A $57$
After using the formula for mean weight we get: $\frac{\sum x_{i}}{7} = 55 k g$ or $\sum x_{i} = 7 \times 55$ or $\sum x_{i} = 385$ .
Which is equivalent to: $(52 + 58 + 55 + 53 + 56 + 54 + x) = 385$ or $275 + 53 + x = 385$ or $53 + x = 110$ or $x = 110 - 53 = 57 k g s$

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The mean weight per teacher in a group of 7 teachers is 55 kg. The individual weights of 6 of them are 52 kg,58 kg,55kg,53 kg, 56 kg and 54 kg, the weight of the other teacher isx kg, then the value of x is

The correct option is A 57After using the formula for mean weight we get: ∑xi7=55kg or ∑xi=7×55 or ∑xi=385.Which is equivalent to: (52+58+55+53+56+54+x)=385 or 275+53+x=385 or 53+x=110 or x=110−53=57kgs

The mean weight per teacher in a group of $7$ teachers is $55$ kg. The individual weights of $6$ of them are $52$ kg, $58$ kg, $55$ kg, $53$ kg, $56$ kg and $54$ kg, the weight of the other teacher is $x$ kg, then the value of $x$ is

The correct option is A $57$
After using the formula for mean weight we get: $\frac{\sum x_{i}}{7} = 55 k g$ or $\sum x_{i} = 7 \times 55$ or $\sum x_{i} = 385$ .
Which is equivalent to: $(52 + 58 + 55 + 53 + 56 + 54 + x) = 385$ or $275 + 53 + x = 385$ or $53 + x = 110$ or $x = 110 - 53 = 57 k g s$