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Arithmetic Mean and Range

The mean x,...

Question

The mean $x, x + 3, x + 6, x + 9$ and $x + 12$ is

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Solution

$x, x + 3, x + 6, x + 9, x + 12$
Mean $= \frac{x + x + 3 + x + 6 + x + 9 + x + 12}{5}$
$= \frac{5 x + 30}{50} = x + 6$

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Similar questions

x, x + 3, x + 6, x + 9

x + 12

Q. If the arithmetic mean of x, x + 3, x + 6, x + 9, and x + 12 is 10, the x =

(a) 1
(b) 2
(c) 6
(d) 4

Q. Find the sum of

6 x^{2} + 12 x y and 9 x^{3} - 6 y x .

Q. The quotient obtained when

15 x^{6} - 9 x^{4} + x^{3} + 6 x + 12

3 x^{2}

\frac{x + 5}{6} . \frac{x - 3}{9} = \frac{x + 2}{12}

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