The measure of angle ACB is .

$60^{\circ}$

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$90^{\circ}$

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$30^{\circ}$

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Solution

The correct option is B $90^{\circ}$

Given, the measure of the exterior angle DAC is 150 degrees.

The exterior angle property states that the measure of an exterior angle of a triangle is equal to the sum of its interior opposite angles.

So,
$∠ A B C + ∠ A C B = ∠ D A C$
$60^{\circ} + ∠ A C B = 150^{\circ}$
$∠ A C B = 90^{\circ}$

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In the given figure, O is the centre of a circle and $∠ A C B = 30^{\circ} . Then, ∠ A O B = ?$

(a) $30^{\circ}$

(b) $15^{\circ}$

(d) $90^{\circ}$

In a parallelogram ABCD if angle A is 60^o then the measure of angle B is:

The measure of an angle which is its own complement is
(a) $30^{\circ}$
(b) $60^{\circ}$
(c) $90^{\circ}$
(d) $45^{\circ}$

In the square ABCD below, what is the measure of $∠ A O B$ ?

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