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B
105∘
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C
100∘
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Solution
The correct option is B105∘ Given the diagram:
Let us first construct a line QOP (from left to right) parallel to lines BA and DC.
Clearly, we can say that: ∠FOQ+∠BFO=180∘ (co-interior angles) ⇒∠FOQ=180∘−105∘=75∘
Also, ∠CEO and ∠EOQ are alternate interior angles. ⇒∠CEO=∠EOQ=30∘
Now, ∠EOF=∠FOQ+∠EOQ ⇒∠EOF=75∘+30∘=105∘