The measure of the smallest angle of pentagon if the angles are in the ratio 1:2:3:4:5 -

16⁰

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26⁰

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32⁰

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36⁰

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46⁰

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Solution

The correct option is D
36⁰

Sum of angles of a pentagon = 540 $^{0}$ Let the smallest angle be `x' x + 2x + 3x + 4x + 5x = 540 $^{0}$ x = 36 $^{0}$

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Similar questions

In a pentagon, if two interior angles are $140^{\circ}$ and $160^{\circ}$ , and the remaining angles are in the ratio 1 : 3 : 4, then its smallest angle measures ____ .

Q. One angle of a pentagon is

140^{\circ}

. If the remaining angles are in the ratio

4 : 2 : 3 : 1

; find the smallest and the largest angles.

If the ratio of angles in the pentagon are in the ratio 1 : 2--k : 3--k : k+ 1 : k + 3 (k<1). Then the measure of the smallest angle of the pentagon will be -

Q. The exterior angles of a pentagon are in the ratio

2 : 1 : 4 : 3 : 5

. Find each angle of the pentagon.

If the ratio of angles in the pentagon are in the ratio 1 : 2--k : 3--k : k+ 1 : k + 3 (k<1). Then the measure of the smallest angle of the pentagon will be -

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The measure of the smallest angle of pentagon if the angles are in the ratio 1:2:3:4:5 -

The correct option is D 360 Sum of angles of a pentagon = 5400 Let the smallest angle be `x' x + 2x + 3x + 4x + 5x = 5400 x = 360

The correct option is D
36⁰

Sum of angles of a pentagon = 540 $^{0}$ Let the smallest angle be `x' x + 2x + 3x + 4x + 5x = 540 $^{0}$ x = 36 $^{0}$