Question

The measure of the third angle of the triangle. ( in degrees )

${40}^{\circ },{75}^{\circ },$ is ${65}^{\circ }$.( Enter 1 if true or 0 otherwise)

Answer 1

Given two angles of the triangle, ${40}^{\circ },{75}^{\circ }$
Let the third angle be $x$
Sum of the angles = 180
$40+75+x=180$
$x=65$
Third angle = ${65}^{\circ }$