Question

The measured resistance of a conductance cell was 100 $\Omega$. ($M_{KCl}=$ $74.5gmo{l}^{-1}$ and cell constant $=1.25c{m}^{-1}$). If the specific conductance in $oh{m}^{-1}c{m}^{-1}$ is $125\times {10}^{-x}$, then what is the value of $x$?

Answer 1

The expression for specific conductance $\kappa$ is:

$\kappa =\frac{\frac{l}{a}}{R}$.

Here $R$ is the resistance and $\frac{l}{a}$ is the cell constant.

Substitute values in the above expression.

$\kappa =\frac{1.25c{m}^{-1}}{100ohms}=0.0125=125\times {10}^{-4}oh{m}^{-1}c{m}^{-1}$.

So, the value of $x=4$.