The measurement of the electron position is associated with an uncertainty in momentum- which is equal to 1 - 10-18 g cm s -1- The uncertainty in electron velocity is mass of an electron is 9 - 10-28 g A- 1 - 1011 cm s -1B- 1 - 109 cm s -1C- 1 X 105 cm s -1D- 1 - 106 cm s -1

The correct option is B 1 X 109 cm s 1P=m V V= P/m=1× 10^ 18/9× 10^ 28=1.11× 10^9 cm s^ 1 ...

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Standard IX

Chemistry

Bohr's Model of an Atom

The measureme...

Question

The measurement of the electron position is associated with an uncertainty in momentum, which is equal to $1 \times 10^{- 18} g c m s^{- 1}$ . The uncertainty in electron velocity is (mass of an electron is $9 \times 10^{- 28} g$ )

1 X 10⁵ cm s^-1

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1 X 10¹¹ cm s^-1

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1 X 10⁹ cm s^-1

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1 X 10⁶ cm s^-1

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Solution

The correct option is C 1 X 10⁹ cm s^-1
$△ P = m △ V$
$△ V = \frac{△ P}{m} = \frac{1 \times 10^{- 18}}{9 \times 10^{- 28}} = 1.11 \times 10^{9} c m s^{- 1}$

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The measurement of the electron position is associated with an uncertainty in momentum, which is equal to 1×10−18 g cm s−1. The uncertainty in electron velocity is (mass of an electron is 9×10−28 g)

The correct option is C 1 X 109 cm s-1△P=m△V △V=△Pm=1×10−189×10−28=1.11×109 cm s−1

The measurement of the electron position is associated with an uncertainty in momentum, which is equal to $1 \times 10^{- 18} g c m s^{- 1}$ . The uncertainty in electron velocity is (mass of an electron is $9 \times 10^{- 28} g$ )

The correct option is C 1 X 10⁹ cm s^-1
$△ P = m △ V$
$△ V = \frac{△ P}{m} = \frac{1 \times 10^{- 18}}{9 \times 10^{- 28}} = 1.11 \times 10^{9} c m s^{- 1}$