Question

The measures of angles of a triangle are $x^o,(x-20{)}^o,(x-40{)}^o$. Find the measure of each angle.

Answer 1

Measure of $1^{st}$ angle $=x^o$

Measure of $2^o$ angle $=(x-20{)}^o$

Measure of $3^{rd}$ angle $=(x-40{)}^o$

By using angle sum property of triangle

$x^o+(x-20{)}^o+(x-40{)}^o={180}^o$

$3x-60=180$

$3x=240$

$x{80}^o$

$\therefore$ Measure of $1^{st}$ angle $=x^o={80}^o$

Measure of $2^{nd}$ angle $=(x-20{)}^o={60}^o$

Measure of $3^{rd}$ angle $=(x-40{)}^o={40}^o$