Question

The measures of the angles of a triangle are in the ratio $5:4:3$. Find the angles of the triangle.

Answer 1

Given that in a $△ABC$, $\angle A:\angle B:\angle C=5:4:3$

Let the angles of the given triangle be $5x^o,4x^o,3x^o$.

We know that the sum of the angles of a triangle is ${180}^o$

$5x^o+4x^o+3x^o={180}^o\Rightarrow 12x^o={180}^o$

$x^o=\frac{{110}^o}{12}={15}^o$

So, the angles of the triangle are ${70}^o,{60}^o,{45}^o$.