Question

The measures of two adjacent angles of a parallelogram are in the ratio $3:2$. Find the measure of smallest of the angles of the parallelogram(in degree).

Answer 1

We know that the sum of the two adjacent angles of a parallelogram is ${180}^o$

The given ratio of the angles is $3:2$

Let the angles be $3x$ and $2x$ to keep up with the given ratio.

$2x+3x={180}^o$

$x={36}^o$

$\therefore 2x={72}^o$ and $3x={108}^o$

Largest angle $={108}^o$ and Smallest angle $={72}^o$