The mechanical advantage of a machine is $2$ . It is used to raise a load of $150 K g f$ . What effort is needed?

Open in App

Solution

Step 1- Given data;
M.A = $2$
Effort =?
Load = $150 K g f$
Step 2 -Formula used;
$M . A = \frac{l o a d}{e f f o r t}$
Step 3-Calculations;
$M . A = \frac{l o a d}{e f f o r t} 2 = \frac{150 k g f}{e f f o r t} e f f o r t = \frac{150}{2} e f f o r t = 75 e f f o r t = 75 k g f$
Hence the value of effort is $75 K g f$ .

Suggest Corrections

Similar questions

Mechanical advantage of a machine is $4$ . It is used to raise a load of $30 k g f$ . What is the effort needed?

A machine has a mechanical advantage of $10$ . It used to lift a load of $200 k g f$ . Find the required effort.

A machine that has a mechanical Advantage of 9 is used for a load of 765 Kgf. Find the required effort.

The mechanical advantage of a machine is $5$ . How much load it can exert for the effort of $2 K g f$ .

Determine the mechanical advantage of a simple machine which helps to lift a load of $75 k g f$ when an effort of $15 k g f$ is applied.

Join BYJU'S Learning Program