The mechanical advantage of a machine is $2$ . It is used to rise a load of $15 k g f$ . What efforts is needed?

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Solution

Given,
Mechanical advantage $= 2$
Load $15 k g f$
Mechanical advantage $= \frac{L o a d}{E f f o r t}$
Effort $= \frac{L o a d}{M e c h a n i c a l a d v a n t a g e}$
$= \frac{15}{2} = 4.5 k g f$

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