The mechanical advantage of a machine is $5$ . How much load it can exert for the effort of $2 K g f$ .

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Solution

Step 1-Given data;
M.A = $5$
Effort = $2 K g f$
Load =?
Step 2 -Formula used and calculation
$M . A = \frac{l o a d}{e f f o r t} 5 = \frac{l o a d}{2 k g f} 5 = \frac{l o a d}{2} l o a d = 5 \times 2 l o a d = 10 k g f$
Hence, the value of the load is $10 K g f$ .

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