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Question

The median for the data is 22.5

Class interval0−1010−2020−3030−40Frequency7151612


A
True
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B
False
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Solution

The correct option is B False
Cumulative frequency which is greater than and closest to 25 is 38. Hence median class is 20 - 30

Class IntervalFrequencyCumulative Frequency01077102015222030163830401250

Median = LRL+(N2fcfm)×i,
where LRL stands for the lower real limit, fm=frequency of median class, fc=cumulative frequency above the median class and i=size of the class interval
Thus, Median=20+252216×10=21.875

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