The median for the following data is _____.
Class interval0−1010−2020−3030−40Frequency7151612
Class IntervalFrequencyCumulative Frequency0−107710−20152220−30163830−401250
In the above distribution the total number of observations is 50. Hence, n = 50.
∴n2=25.
The cumulative frequency that is greater than 25 but closest to 25 is 38. The class corresponding to this frequency is 20 - 30.
This is the median class.
Using Median = l+(n2−cff)×h
Where l is lower class limit of median class.
n is total number of observations.
cf is the cumulative frequency of the class preceding the median class.
f is the frequency of the median class and h is the class size.
∴Median=20+25−2216×10=21.875