Question

The median of $1,3,2,5,8,6,1,4,7,9=\frac{1}{2}(5\mathrm{th}\mathrm{term}+6\mathrm{th}\mathrm{term})=\frac{1}{2}(8+6)=7$.

Answer 1

We will arrange the given numbers in ascending order as:
1, 1, 2, 3, 4, 5, 6, 7, 8, 9
Here, n is 10, which is an even number.
Thus, we have:
$$\begin{gathered} \mathrm{Median}=\mathrm{Mean}\mathrm{of}\left(\frac{n}{2}\right)\mathrm{th}\&\left(\frac{n}{2}+1\right)\mathrm{th}\mathrm{term}s \\ =\frac{1}{2}\left(5\mathrm{th}\mathrm{term}+6\mathrm{th}\mathrm{term}\right) \\ =\frac{1}{2}\left(4+5\right)=\frac{9}{2}=4.5 \end{gathered}$$

Therefore, the given statement is false.