Question

The median of a symmetrical distribution, whose lower and upper quartiles are 60 and 80 respectively, is

• A. 60
• B. 80
• C. 70
• D. None of these

Answer 1

The correct option is C 70

Given, lower quartile $=60$ and upper quartile $=80$
$\therefore$ median $=\frac{\text{lower quartile}+\text{upper quartile}}{2}=\frac{60+80}{2}=70$