The median of any triangle bisects it into two triangles of equal areas.
True
Consider the figure:
The median AD bisects △ABC into two triangles △ABD and △ACD.
We have to check whether area of △ABD= area of △ACD.
To check that, draw AE⊥BC
Now, area of △ABD=12×BD×AE ... (i)
area of △ACD=12×CD×AE ... (ii)
Since, AD is the median, so, BD=CD
⇒ Eq. (i) = Eq. (ii)
⇒ area of △ABD= area of △ACD
Thus, the given statement is true.