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Question

The median of the following data is 525. Find the value of x and y, if the sum of frequency is 100.
1140942_f409526ec9eb457390cf4fc41a8b0335.JPG

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Solution

Class Interval Frequency Combine Frequency
01003 3
1002004 3+4=7
200300X x+7
30040012 x+7+12=x+19
40050017 x+19+17=[x+36]
50060020 x+36+20=x+56
600700 9 x+56+9=x+65
700800 Y x+65+y=X+Y+65
$800-900 8 x+Y+65+8=X+Y+73
9001000 3 x+y+73+3=X+Y+76
Median 525 (Median class :500600)
h=100
Median =l+n/2c.ff×h
525=500+100/2(x+36)20×100
25100×20=50x36
x=9
fi76+Y+X=100
9+Y=10076
Y=249
=15
X,Y9,15

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