The median of the given dataset 41, 43, 127, 58, 99, 92, 61, 71 and 57 is .

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Solution

Given data are 41, 43, 127, 99, 61, 92, 71, 58 and 57.

Arranging in ascending order, $41, 43, 57, 58, 61, 71, 92, 99, 127$ . Here n = 9 which is an odd number.
$∴ Median = \frac{n + 1}{2} t h t e r m$
$= \frac{10}{2} t h t e r m$
$= 5 t h t e r m$
$= 61$
$The median of the given data is 61.$

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