The median of the numbers $6, 14, 12, 8, 10, 9, 11$ is

8

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10

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10.5

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11

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Solution

The correct option is B $10$
Arranging given observations in ascending order,
$6, 8, 9, 10, 11, 12, 14$
Clearly number of terms is 7 (odd)
Hence required median $= {(\frac{7 + 1}{2})}^{t h}$ term $= 10$

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Similar questions

Q. Find the median of the following numbers

11, 13, 8, 10, 15, 18, 12, 7, 9, 16

Q. Numbers

50, 42, 35, 2 x + 10, 2 x - 8, 12, 11, 8

are written in descending order and their median is

25

find

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The median of first 8 prime numbers is

(a) 7 (b) 9 (c) 11 (d) 13

Q. The frequency table shows the number of chocolates that were distributed among the students of different grades. Find the median number of grade students.

Grade	$6$	$7$	$8$
Number of chocolates distributed	$10$	$24$	$11$

Complete the table below:

$\begin{matrix} O u t p u t (U n i t s) & A v e r a g e C o s t (R s .) & M a r g i n a l C o s t (R s .) 1 & 12 & - 2 & 10 & - 3 & - & 10 4 & 10.5 & - 5 & 11 & - 6 & - & 17 \end{matrix}$

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The median of the numbers 6,14,12,8,10,9,11 is

The correct option is B 10Arranging given observations in ascending order, 6,8,9,10,11,12,14Clearly number of terms is 7 (odd)Hence required median =(7+12)th term =10

The median of the numbers $6, 14, 12, 8, 10, 9, 11$ is

The correct option is B $10$
Arranging given observations in ascending order,
$6, 8, 9, 10, 11, 12, 14$
Clearly number of terms is 7 (odd)
Hence required median $= {(\frac{7 + 1}{2})}^{t h}$ term $= 10$