Question

The medians of a triangle meet at $(0,-3)$ and its two vertices are at $(-1,4)$ and $(5,2)$. Then the third vertex is at-

• A. $(4,15)$
• B. $(-4,-15)$
• C. $(-4,15)$
• D. $(4,-15)$

Answer 1

The correct option is B $(-4,-15)$

$(0,3)\equiv [\frac{x-1+5}{3},\frac{y+4+\alpha }{3}]$

$(0,3)\equiv [\frac{4+4}{3},\frac{y+6}{3}]$

On comparing

$\frac{x+4}{3}=0,\frac{y+6}{3}=-3$

$x+4=0,y+6=-9$

$x=-4y=-15$

So, coordination = $(-4,15)$