Question

The melting point of cadmium bromide is ${568}^{\circ }C$. Which of the following equations best describes what occurs when cadmium bromide is heated to ${568}^{\circ }C$?

• A. $CdBr\left(s\right)\to CdBr\left(l\right)$
• B. $CdB{r}_2\left(s\right)\to CdB{r}_2\left(l\right)$
• C. $CdB{r}_2\left(s\right)\to Cd\left(s\right)+B{r}_2\left(g\right)$
• D. $CdB{r}_2\left(s\right)\to C{d}^{2+}\left(aq\right)+2B{r}^{-}\left(aq\right)$

Answer 1

The correct option is B $CdB{r}_2\left(s\right)\to CdB{r}_2\left(l\right)$

Melting point is defined as the temperature at which solid is converted to liquid.

Given, Melting point of $Cd{Br}_2={568}^{0}C$

So, At ${568}^{0}C$

${CdBr}_2\left(solid\right)⟶{CdBr}_2\left(liquid\right)$

Ans :- A