The melting point of ice can be given by:

32^{\circ} F

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32^{\circ} C

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273.15 K

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Both a and c

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Solution

The correct option is D Both a and c
The relation between Celsius and Fahrenheit is given by $\frac{C}{100} = \frac{F - 32}{180}$
The relation between Celsius and Kelvin is given by, $K = C + 273.15$
So, melting point of ice $= 0^{o} C = 32^{o} F = 273.15 K$

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I don't understand how melting point = freezing point.

For example, if liquid water freezes at 0 °C how can ice also melts at 0 °C?

13^{0} C

f (x) = \frac{9 x}{5} + 32

x^{\circ} C

^{\circ} C

F - 32 = \frac{9}{5} C

C = 40^{\circ}

m

θ (i n^{\circ} C)

M

c

L

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