The correct option is C BeCO3
Beryllium carbonate BeCO3 decomposes easily on heating due to following two factors:
(1) The small Be2+ ion has high polarisation power and the carbonate ion has high polarisability.
(2) It rapidly decomposes to BeO(s) and CO2(g). The decomposition product, i.e., beryllium oxide has high stability due to tight packing of Be2+ ion and oxide ion.