Question

The metal strontium forms ions with the symbol $S{r}^{2+}$. Write down the formula for each of the following:
i) Strontium oxide ii) Strontium chloride iii) Strontium nitrate iv) Strontium sulphate

Answer 1

(i) Oxide has $O^{2-}$ ion, strontium ion is $S{r}^{2+}$. Hence by balancing the charge, strontium oxide has the formula $SrO$.

(ii) Chloride has $C{l}^{-}$ ion. To balance $+2$ charge, we need $2C{l}^{-}$ ions. Hence formula of strontium chloride is $SrC{l}_2$.

(iii) Nitrate ion is $(N{O}_3{)}^{-}$. We need $2$ nitrate ions to balance the $+2$ charge of $S{r}^{2+}$. Hence strontium nitrate is $Sr(N{O}_3{)}_2$.

(iv) Sulphate ion is $(S{O}_4{)}^{2-}$. We need $1$ suphate ion to balance the $+2$ charge. Hence, $SrS{O}_4$ is the formula of strontium sulphate.