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The metals of...

Question

The metals of group 2 from top to bottom are Be, Mg, Ca, Sr, and Ba:
(i) Which of these elements will form ions most readily and why?

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Solution

Among Be, Mg, Ca, Sr, and Ba, Barium (Ba) has the largest size.

So, Ba will be having lowest ionization potential.

So, the removal of electrons from Ba becomes easier. Therefore, Ba forms ions most readily.

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Q. The following questions refer to the Periodic Table.
(a) (i) Name the first and last element in period 2.
(ii) What happens to the atomic size of elements moving from top to bottom of a group?
(iii) Which of the elements has the greatest electron affinity among the halogens?
(iv) What is the common feature of the electronic configurations of the elements in group 7?

(b) Supply the missing word from those in the brackets:
(i) If an element has a low ionization energy then it is likely to be _________ (metallic/non-metallic).
(ii) If an element has seven electrons in its outermost shell then it is likely to have the ________ (largest/smallest) atomic size among all the elements in the same period.

(c) (i) The metals of Group 2 from top to bottom are: Be, Mg, Ca, Sr, Ba. Which of these metals will form ions most readily and why?
(ii) What property of an element is measured by electronegativity?

Q. The metals group 2 from top to bottom are

B e, M g, C a, S r, B a

(i) Which one of these elements will form ions most readily and why?

The metal of group 2 from top to bottom are Be, Mg, Ca, Sr and Ba. Which of these elements will form ions most readily and why?

The metals of group 2 from top to bottom are Be, Mg, Ca, Sr, Ba. Which of these metals will form ions most readily and why?

The metals of group 2 from top to bottom are Be, Mg, Ca, Sr and Ba which of these metals will form ions more readily and why?

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