The mid-point of the line $(a, 2)$ and $(3, 6)$ is $(2, b)$ . Find the numerical values of $a$ and $b$ .

a = 1

b = 6

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a = 2

b = 4

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a = 1

b = 4

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a = 2

b = 6

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Solution

The correct option is D $a = 1$ , $b = 4$
Mid-point of $(a, 2)$ and $(3, 6)$ is $(2, b)$
=> $(2, b) = (\frac{a + 3}{2}, \frac{2 + 6}{2}) => a = 4 - 3, b = 4 => a = 1, b = 4$

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