The mid-point of the segment joining common points of $2 x - 3 y + 8 = 0$ and $y^{2}$ = 8x is

(3 , 2)

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(4 , 1)

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(5 , 6)

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(5 , 2)

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Solution

The correct option is C (5 , 6)

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Similar questions

2 x - 3 y + 8 = 0

y^{2} = 8 x

2 x - 3 y + 8 = 0

y^{2} = 8 x,

2 x - 3 y + 8 = 0

y^{2} = 8 x,

Ratio in which line $2 x + 3 y - 5 = 0$ divides the line segment joining the points A(8 , -9) and B(2 , 1) is .

2 x - 3 y + 4 = 0, x - 2 y + 3 = 0

(3, - 2)

(- 5, 8)

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