Question

The mid – point of the sides of at triangle ABC along with any of the vertices as the fourth point make a parallelogram of area equal to:

• A.
• B.
• C.
• D. Can’t determined

Answer 1

The correct option is B

We know,
Area of parallelogram = base $\times$ height

Now, ar (DECF) = ar (EC $\times$ EG)
$ar\left(DECF\right)=\left(\frac{1}{2}\right)BC\times \left(\frac{1}{2}\right)AE$ [E is mid - point of BC]
$ar\left(DECF\right)=\left(\frac{1}{2}\right)ar\Delta ABC$
Hence, (b) is correct option.