△ABC is an equilateral triangle. D, E, and F are the mid points of sides AB, BC, and AC, respectively.
By mid point theorem,
DE || AC and DE = 12 AC --------------- (I)
DF || BC and DF = 12 BC -------------- (II)
EF || AB and EF = 12 AB -------------- (III)
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Since ABC is an equilateral triangle,
⇒ AB = BC = AC
Therefore, DE = DF = EF = 12AB
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Hence, ΔDEF is equilateral with each side being 5cm.
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