The middle term in the expansion of 1- x 2 nA- 1-3 -5 -5 n-1- B- 2-4 -6 - 2 n-n - xn xnC- 1-3 -5 -2 n-1-n - xnD- 1-3 -5 -2 n-1-n - 2n xn

The correct option is D Middle term of (1+x)^2n is T_n+1=^2nC_nx^n =(2n)!/n!n!x^n=1.3.5⋯ (2n 1)/n!2^nx^n ...

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nCr Definitions and Properties

The middle te...

Question

The middle term in the expansion of $(1 + x)^{2 n}$

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Similar questions

The middle term in the expansion of $(1 + x)^{2 n}$ is

(1 + x)^{2 n}

\frac{1.3.5... (2 n - 1)}{(n)!} 2^{n} x^{n}

(1 + x)^{2 n}

\frac{1.3.5... (2 n - 1)}{n!}

2^{n} x^{n}

{(1 + x)}^{2 n}

\frac{1.3.5.... (2 n - 1)}{| n - -} 2^{n} x^{n}

Show that the middle term in the expansion of $(1 + x)^{2 n}$ is $\frac{1. 3.5 \dots (2 n - 1)}{n!} . 2^{n} . X^{n}, where n ϵ N .$

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