The middle term in the expansion of 1-x2 n isA- 1-3 -5 -5 n-1-n - xnB- 2-4 -6 - -2 n-n x2 n-1C- 1-3 -5 -2 n-1-n - x-D- 1-3 -5 -2 n-1-n - 2- xn

The correct option is D Middle term of (1 + 2x)^2n is T_n+1 = nbsp;^2n C nbsp;_nx^n = nbsp; (2n)!/n!n!x^n = nbsp; 1.3.5.......(2n 1)/n! 2^nx^n. ...

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Middle Terms

The middle te...

Question

The middle term in the expansion of $(1 + x)^{2 n}$ is

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(1 + x)^{2 n}

Show that the middle term in the expansion of $(1 + x)^{2 n}$ is $\frac{1. 3.5 \dots (2 n - 1)}{n!} . 2^{n} . X^{n}, where n ϵ N .$

(1 + x)^{2 n}

\frac{1.3.5... (2 n - 1)}{(n)!} 2^{n} x^{n}

(1 + x)^{2 n}

\frac{1.3.5..... (2 n - 1)}{n!}

2^{n} x^{n}

{(1 + x)}^{2 n}

\frac{1.3.5.... (2 n - 1)}{| n - -} 2^{n} x^{n}

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