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Question

The middle term in the expansion of (axbx2)12 is:

A
984a6b6x6
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B
924a5b5x5
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C
628a6b6x6
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D
924a6b6x6
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Solution

The correct option is D 924a6b6x6
Total number of the terms in the given expansion will be n+1=13
Hence, middle term of the expansion will be 13+12=7

T6+1=12C6×a6b6×x6
=(12×11×10×9×8×76×5×4×3×2×1×a6b6x6)=924a6b6x6

Hence, the middle term in the given expansion is 924a6b6x6.

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