Question

The middle term in the expansion of ${(\frac{a}{x}+bx)}^{12}$ is

• A. $924a^6{b}^6$
• B. $924a^6{b}^5$
• C. $924a^5{b}^5$
• D. $924a^5{b}^6$

Answer 1

The correct option is A $924a^6{b}^6$

The middle term will be the 7th term.
Hence
$T_{6+1}={}^{12}{C}_6\left(\frac{a}{x}{)}^6\right(bx{)}^6=924a^6{b}^6$