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Question

The middle term of (1−3x+3x2−x3)2n is

A
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B
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C
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D
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Solution

The correct option is A
(13x+3x2x3)2n =[(1x)3]2n =(1x)6n
Middle term = (6n2+1)th term =(3n+1)th term = 6nC3n(x)3n

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