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Question

The middle term(s) in the expansion of (3x−x36)7 is/are:

A
105x138
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B
35x1548
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C
35x1373
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D
105x1548
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Solution

The correct options are
A 105x138
B 35x1548
Clearly, the given expansion has 7+1=8 terms.
So, it has two middle terms, namely 82,82+1, i.e., 4th and 5th terms
Now, T4=T(3+1)
=(1)3×7C3×(3x)(73)×(x36)3
=105x138
And, T5=T(4+1)
=(1)4×7C4×(3x)(74)×(x36)4
=35x1548
Hence, the required middle terms are 105x138 and 35x1548

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