The midpoint of line segment joining (2a, 4) & (–2, 2b) is (2, 2a + 1). Find the values of a & b.

a = 3, b = 3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

a = 2, b = 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a = 2, b = 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a = 3, b = 5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

a = 3, b = 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a = 2, b = 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
A
a = 3, b = 3

D
a = 3, b = 5

Suggest Corrections

Similar questions

The mid-point of the line segment joining (2a, 4) and (-2, 2b) is (1, 2a + 1). Find the values of a and b.

(2 a, 4)

(- 2, 2 b)

(1, 2 a + 1)

(2 a + 2, 3)

(4, 2 b + 1)

(2 a, 2 b)

a

b

The mid-point of the line segment joining $(2 a, 4)$ and $(- 2, 2 b)$ is $(1, 2 a + 1)$ . Then the values of $a$ and $b$ respectively are

Join BYJU'S Learning Program