The midpoint of line segment joining A(2,3) and B(4,5) lies on the curve.

x + y = 5

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x^{2} + y^{2} = 25

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x + 2 y = 8

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Solution

The correct option is B $x^{2} + y^{2} = 25$
Midpoint of line segment = $(\frac{2 + 4}{2}, \frac{3 + 5}{2}) = (3, 4)$ and (3,4) follows the equation of the curve $x^{2} + y^{2} = 25$ .

So the midpoint of the line segment joining A(2,3) and B(4,5) lies on the curve $x^{2} + y^{2} = 25$ .

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Question 5
Plot the points A (1, -1) and B(4, 5).
(i) Draw the line segment joining these points. Write the coordinate of a point on this line segment between the point A and B.
(ii) Extend this line segment and write the coordinates of a point on this line which lies outside the line segment AB.

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The midpoint of line segment joining A(2,3) and B(4,5) lies on the curve.

The correct option is B x2+y2=25Midpoint of line segment = (2+42,3+52)=(3,4) and (3,4) follows the equation of the curve x2+y2=25. So the midpoint of the line segment joining A(2,3) and B(4,5) lies on the curve x2+y2=25.

The correct option is B $x^{2} + y^{2} = 25$
Midpoint of line segment = $(\frac{2 + 4}{2}, \frac{3 + 5}{2}) = (3, 4)$ and (3,4) follows the equation of the curve $x^{2} + y^{2} = 25$ .

So the midpoint of the line segment joining A(2,3) and B(4,5) lies on the curve $x^{2} + y^{2} = 25$ .