The midpoints D and E of the sides AB and AC of an equilateral triangle are joined together to form a line segment DE. If AD = 4cm, then find DE.

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Solution

The correct option is B
4

$A B C$ is an equilateral traingle. And $A D$ = 4
Since D is the midpoint of AB,
$A B = 2 \times A D = 8 c m .$

Since, it is given that ABC is an equilateral triangle; all sides are equal to 8 cm.

Now, using midpoint theorem, we can say that DE = $\frac{1}{2}$ BC = 4 cm.

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The midpoints D and E of the sides AB and AC of an equilateral triangle are joined together to form a line segment DE. If AD = 4cm, then find DE.

The correct option is B 4 ABC is an equilateral traingle. And AD = 4 Since D is the midpoint of AB, AB=2×AD=8 cm. Since, it is given that ABC is an equilateral triangle; all sides are equal to 8 cm. Now, using midpoint theorem, we can say that DE = 12 BC = 4 cm.